Fullerton, Nebraska
Fullerton is a city in
Nance County,
Nebraska,
United States. The population was 1,378 at the 2000 census. It is the
county seat of
Nance County.
 |
Location of Fullerton, Nebraska |
Fullerton is located at (41.363009, -97.970858).
According to the
United States Census Bureau, the city has a total area of 3.2
km² (1.2
mi²), all land.
As of the
census of 2000, there were 1,378 people, 551 households, and 375 families residing in the city. The
population density was 429.1/km² (1,110.0/mi²). There were 636 housing units at an average density of 198.0/km² (512.3/mi²). The racial makeup of the city was 96.95%
White, 0.80%
Native American, 0.07%
Asian, 1.09% from
other races, and 1.09% from two or more races.
Hispanic or
Latino of any race were 2.47% of the population.
There were 551 households out of which 29.6% had children under the age of 18 living with them, 55.4% were
married couples living together, 9.1% had a female householder with no husband present, and 31.9% were non-families. 30.3% of all households were made up of individuals and 16.9% had someone living alone who was 65 years of age or older. The average household size was 2.37 and the average family size was 2.94.
In the city the population was spread out with 25.9% under the age of 18, 6.7% from 18 to 24, 20.6% from 25 to 44, 22.2% from 45 to 64, and 24.5% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 96.0 males. For every 100 females age 18 and over, there were 88.7 males.
The median income for a household in the city was $31,055, and the median income for a family was $39,087. Males had a median income of $26,528 versus $19,063 for females. The
per capita income for the city was $17,593. About 8.5% of families and 12.0% of the population were below the
poverty line, including 17.2% of those under age 18 and 10.3% of those age 65 or over.
