Advanced Math/Trigonometric Functions
Expert: Steve Holleran - 1/4/2008
QuestionI'm sorry to bother you again. But can you help me with these too. I need to finish my trig course asap and I don't understand the convoluted language of the lesson.
9. Arccot (-0.555)
12. 2cos(x) - 2 = -1
Just checking: I got this: 120° + 360°n, 240° + 360°n
13. sec(x) + 4 = 2
14. sin(x)cos(x)=0, where 0 < x <2pi
15. sin2(x) - 5 = cos2(x) - 1
16. sin2(x) + sin(x) = 2, where 0 < x <2pi
I got this: 2pi/3, + 2pin
17. cos(1/2x) = 1/2
18. 4cos2(x) = 3
19. sin(x) = 2 cos2(x) - 1
20. sin2(2x) = 1
21. 4 sin(x)cos(x) - 2sin(x) - 2cos(x) = -1, where 0 < x <2pi
Thank you in advance for your help.
AnswerHi Sana,
Whew! This is a lot to ask all at once. Can you try to send them in smaller groups in the future?
Anyway, let's see:
9. If Arccot(-0.555) = x, then cot x = -.555 = 1/ tan x
so tan x = 1/-.555 and x = Arctan(1/-.555) = -1.06 radians.
12. 2 cos x - 2 = -1 -----> 2 cos x = 1
so cos x = 1/2 ---> x = 60 + 360n ; 300 + 360n
13. sec x + 4 = 2 ----> sec x = -2 --> cos x = -1/2
so x = 120 + 360n ; 240 + 360n
14. if sin x * cos x = 0 then either
sin x = 0 -----> x = 0, pi
cos x = 0 ----> x = pi/2, 3pi/2
15. Here, if you rearrange, you can get:
sin 2x - cos 2x = 4
Since sin 2x at most can = 1, and cos 2x at least can
= -1, the largest difference can be 2. So here there
is no solution.
16. sin 2x + sin x = 2
Again, since sine values have a max of 1, this will
only happen if sin 2x = 1 AND sin x = 1. But if sin x = 1, then x = pi/2, which makes 2x = pi, and the sin pi = 0,
so here there is no solution.
17. cos (1/2 x) = 1/2--> 1/2 x = 60 or 1/2 x = 300
which makes x = 120 +/- 360n or x = 600 +/- 360n
18. 4 cos 2x = 3 ---> cos 2x = 3/4 --> 2x = 0.7227 rad
so x = .3614 radians
19. sin x = 2 cos 2x - 1
sin x + 1 = 2 cos 2x --> sin x + 1 = 2(1 - 2 sin^2 x)
sin x + 1 = 2 - 4 sin^2 x
4 sin^2 x + sin x - 1 = 0
Now use the quadratic formula to get
sin x = .3903 ----> x = Arcsin(.3903) = .4009 rad
sin x = -.6403 --> x = Arcsin(-.6403) = -.6949 rad
20. sin 2(2x) = 1 ----> sin 4x = 1
4x = pi/2 ; 5pi/2; 9pi/2 ; 13pi/2 etc
x = pi/8 ; 5pi/8 ; ......
21. 4 sin x cos x - 2 sin x - 2 cos x = -1
4 sin x cos x - 2 sin x - 2 cos x + 1 = 0
now factor by grouping:
2 sin x(2 cos x - 1) - 2 cos x + 1 = 0
2 sin x(2 cos x - 1) -1(2 cos x - 1) = 0
(2 cos x - 1)(2 sin x - 1) = 0
so either 2 cos x - 1 = 0 --> cos x = 1/2
x = pi/3, 5pi/3
or 2 sin x - 1 = 0 --> sin x = 1/2
x = pi/6 , 5pi/6
Hope this helps you out, and that you finish your trig course satisfactorily.
Steve