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Advanced Math/Calc: Limits
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Question
how do i go about answering this? I thought that factoring would be involved but how do i go about factoring the top to (x-6)?
lim (x^3-9x^2+23x-30)/(x-6)
x->6
(x^3 - 9x^2 + 23x - 30)/(x - 6)
i'd use synthetic division
6`|`1`-9``23``|`-30
``|````6`-18``|``30
--------------------
``|`1`-3```5``|```0
so when you divide (x^3 - 9x^2 + 23x - 30) by (x - 6)
you get
x^2 - 3x + 5 as your result.
as far as using limitations, i'm not certain since i've never done limitations.
but your y-value would be y > 23
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Sherman D.
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