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Advanced Math/Solving Systems of equations in three variables
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Question
x + 2y + 3z =5
3x + 2y -2z = -13
5x + 3y -z = -11
x + 2y + 3z = 5
3x + 2y - 2z = -13
5x + 3y - z = -11
x = -2y - 3z + 5
3(-2y - 3z + 5) + 2y - 2z = -13
5(-2y - 3z + 5) + 3y - z = -11
-6y - 9z + 15 + 2y - 2z = -13
-10y - 15z + 25 + 3y - z = -11
-4y - 11z = -28
-7y - 16z = -36
Multiply top by -7 and bottom by 4
28y + 77z = 196
-28y - 64z = -144
13z = 52
z = 4
x = -2y - 3(4) + 5
x = -2y - 12 + 5
x = -2y - 7
3(-2y - 7) + 2y - 2(4) = -13
-6y - 21 + 2y - 8 = -13
-4y - 29 = -13
-4y = 16
y = -4
x = -2(-4) - 7
x = 8 - 7
x = 1
ANS:
x = 1
y = -4
z = 4
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| Comment | Thank you soo much for your help! I've been trying to solve these problems for a while now and i finally realized where i went wrong. it would be great if you could also help me with the other 2 questions i submitted. Thanks again! | ||
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