Advanced Math/Symmetry And Coordinate Graphs
Expert: Paul Klarreich - 3/7/2008
QuestionI have quite a few questions but i need them tonight i could really use your help i am struggling during this unit!!
1.determine whether each graph is symmetric with respect to the x-axis, the y-axis, the line y=x, the line y=-x, the origin, or none of these.
a.x^2 y^2=9
b.5x^2 6x-9=y
2.Use the graph of the parent graph F(x)=x^2 to describe the changes between each function. Use complete sentences.
a.g(x)=(x-6)^2
b.h(x)=4(x 1)^2-8
3.Find the inverse algebraically. f(x)=(x-3)^2 7
AnswerQuestioner: David Vacha
Category: Advanced Math
Private: No
Subject: Symmetry And Coordinate Graphs
Question: I have quite a few questions but i need them tonight i could really use your help i am struggling during this unit!!
1.determine whether each graph is symmetric with respect to the x-axis, the y-axis, the line y=x, the line y=-x, the origin, or none of these.
a.x^2 y^2=9
b.5x^2 6x-9=y
2.Use the graph of the parent graph F(x)=x^2 to describe the changes between each function. Use complete sentences.
a.g(x)=(x-6)^2
b.h(x)=4(x 1)^2-8
3.Find the inverse algebraically. f(x)=(x-3)^2 7
...........................................
Hi, David,
Here's what you do for:
Symmetry:
1. Replace x by (-x) [USE PARENTHESES]. Does it come out the same? L-R or y-axis symmetry.
2. Replace y by (-y) [USE PARENTHESES]. Does it come out the same? U-D or x-axis symmetry.
3. Do both. Does it come out the same? Origin symmetry.
4. Swap the letters x and y. Does it come out the same? Symmetry w.r.t y=x
5. [this one is not common and I am not totally sure of it.]
Swap the letters x and y AND replace both x,y with (-x,-y). Does it come out the same? Symmetry w.r.t y=-x
2.Use the graph of the parent graph F(x)=x^2 to describe the changes between each function.
>> this is translation, stretching, etc.
Use complete sentences.
>> Oh, please! You do that anyway, don't you?
a.g(x)=(x-6)^2
Replace x by (x-a). [USE PARENTHESES] Moves the graph 'a' units to the right.
In this case, it moves the graph 6 units to the right.
b.h(x)=4(x 1)^2-8
???????. did you mean (x+1)?
Changes:
x^2 --> (x + 1)^2. Moves 1 unit to the left.
(x + 1)^2 --> 4(x + 1)^2. Stretches vertically by a factor of 4.
4(x + 1)^2 --> 4(x + 1)^2 - 8. Moves 8 units DOWN.
.....................................
3.Find the inverse algebraically. f(x)=(x-3)^2 7
Are you having trouble with the '+' sign? [I know the interface on this site might do that. I will assume you meant:
f(x)=(x-3)^2 + 7
OOps -- I think we are in trouble here, as you will see.
Step 1: Put y in place of f(x):
f(x) = (x-3)^2 + 7
y = (x-3)^2 + 7
Step 2: Swap the letters x and y:
y = (x-3)^2 + 7
x = (y-3)^2 + 7
Step 3. Solve algebraically for y:
x - 7 = (y-3)^2
y - 3 = +- sqrt(x - 7) << That's the oops. Can't have +- here; you get two functions, not one and that is a no-no.
y = 3 +- sqrt(x - 7)
Step 4: Put f-inv(x) in place of y:
f-inv(x) = 3 +- sqrt(x - 7)
Well, we tried.