Expert: Sherman D. - 4/14/2008

Question
In Math
We Have,
         n\(n+1)
        =(n^2-n)\(n^2-1)      (By multiply (n+1))
      Then
 n\(n+1)   =   (n^2-n)\(n^2-1)
Putting  n=1 in above equation,
    1\2 = 0
BUT How This Can Be Possible?????

Answer
if you are saying that your problem is

n/(n + 1) = (n^2 - n)/(n^2 - 1)
n/(n + 1) = (n(n - 1))/((n + 1)(n - 1))
n/(n + 1) = n/(n + 1)

then your problem would have infinite solutions, except n cannot equal -1 or 1, because of your problem on the right side of the equal sign.

so all other numbers except for -1 and 1 will work for your problem.

keep in mind that a number divided by 0 has no solution.