Expert: Sherman D. - 5/15/2008

Question
I cannot seem to figure out log 3(2x-7)=2 and also
Writing
2log^5(3x+2)-[3log^5(x-5)=2log^5x]    write as single log

Answer
if by this you mean

log(3)(2x - 7) = 2
log(2x - 7)/log(3) = 2
log(2x - 7) = 2log(3)
log(2x - 7) = log(3^2)
2x - 7 = 9
2x = 16
x = 8

but if you mean

log(3(2x - 7)) = 2
3(2x - 7) = 10^2
2x - 7 = (100/3)
2x = (21/3) + (100/3)
2x = (121/3)
x = (121/6)

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on this one if you mean

on this one, is the 5s bases, and whats with the [3log^5(x-5)=2log^5x], its in brackets and there's an equal sign.

either way

zlog(x)y = log(x)(y^z)

the negative values go on the bottom, and the positive values go on top., then simplify if possible.

if you meant

2log^5(3x + 2) - 3log^5(x - 5) = 2log^5x

then

if you mean + instead of =, then let me know, and if the bracket part is suppose to be multiplied by the negative, then let me know.