	AllExperts > Experts
	Search

About Sherman D.
Expertise
I can answer questions dealing in mathematics of all kinds except for Physics and Calculus, but i can answer questions in Pre-Calculus and Chemistry. I can also answer questions in Recipes of all kinds. I can find games cheats/walkthroughs, but i can`t find a specific game online or offline. I can also do history and recipes for alcoholic beverages.

Experience
Mathematics, Recipes, History, and Games.

Education/Credentials
High School graduated. I graduated with honors, and i was in Beta Club for a year and a half.

Awards and Honors
Principle's list and A and B honor roll in high school only.

You are here: Experts > Science > Mathematics > Advanced Math > Logarithim

Topic: Advanced Math

Expert: Sherman D.
Date: 5/15/2008
Subject: Logarithim

Question
I cannot seem to figure out log 3(2x-7)=2 and also
Writing
2log^5(3x+2)-[3log^5(x-5)=2log^5x] write as single log

Answer
if by this you mean

log(3)(2x - 7) = 2
log(2x - 7)/log(3) = 2
log(2x - 7) = 2log(3)
log(2x - 7) = log(3^2)
2x - 7 = 9
2x = 16
x = 8

but if you mean

log(3(2x - 7)) = 2
3(2x - 7) = 10^2
2x - 7 = (100/3)
2x = (21/3) + (100/3)
2x = (121/3)
x = (121/6)

-------------------------------------------

on this one if you mean

on this one, is the 5s bases, and whats with the [3log^5(x-5)=2log^5x], its in brackets and there's an equal sign.

either way

zlog(x)y = log(x)(y^z)

the negative values go on the bottom, and the positive values go on top., then simplify if possible.

if you meant

2log^5(3x + 2) - 3log^5(x - 5) = 2log^5x

then

if you mean + instead of =, then let me know, and if the bracket part is suppose to be multiplied by the negative, then let me know.

Add to this Answer Ask a Question

About Us | Advertise on This Site | User Agreement | Privacy Policy | Help
Copyright © 2008 About, Inc. About and About.com are registered trademarks of About, Inc. The About logo is a trademark of About, Inc. All rights reserved.