AboutPaul Klarreich Expertise I can answer questions in basic to advanced algebra (theory of equations, complex numbers), precalculus (functions, graphs, exponential, logarithmic, and trigonometric functions and identities), basic probability, and finite mathematics, including mathematical induction.
I can also try (but not guarantee) to answer questions on Abstract Algebra
-- groups, rings, etc. and Analysis -- sequences, limits, continuity.
I won't understand specialized engineering or business jargon.
Experience I taught at a two-year college for 25 years, including all subjects from algebra to third-semester calculus.
10please help me again please please please thanks!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
use the method in art.23 to solve the triangle ABC,given that a=21.46 ft,b=46.28ft,and C=32° 28'30"
ive attached an image of an example problem just like this but i cant figure out how to get the values of A, B, & C
can you check it for me ! this is my answer
please do check what ive done wrong
a=27
b=21
c=24
_________
2s=72
s=36
s-a=9
s-b=15
s-c=12
log(s-a)=0.95424
log(s-b)=1.17609
log(s-c)=1.07918
________________
3.20951
log s=1.55630
_________________
2)1.65321
___________________
log r=0.82661
log r=0.82661
log(s-a)=0.9524
________
A
log tan __ = 0.86625-10
2
A r
tan----= ---
2 s-a
=0.82661
-------
0.95424
=0.86625
A=------this is i dont know how to get ive tried a lot pls give it to me thanks also the B and C
log r=0.82661
log (s-b)=1.17609
B
log tan --- =0.70285-10
2
B=
log r=0.82661
log(s-c)=1.07918
C
log tan---=0.76596-10
C=
Answer Questioner: grace
Category: Advanced Math
Private: No
Subject: plane trigonometry
Question:
please help me again please please please thanks!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
use the method in art.23 to solve the triangle ABC,given that a=21.46 ft,b=46.28ft,and C=32° 28'30"
ve attached an image of an example problem just like this but i cant figure out how to get the values of A, B, & C
..........................................
Hi, Grace,
I'll try, but it really isn't fair for you to insist I figure a method that you are not sending me.
..................
can you check it for me ! this is my answer
please do check what ive done wrong
a=27
b=21
c=24
>> I'll assume these are the values and go on from there. [Not consistent with what you wrote.]
_________
2s=72 << write out here: 2s = a + b + c.
s=36 = the 'semiperimeter.'
s-a=9
s-b=15
s-c=12
log(s-a)=0.95424
log(s-b)=1.17609
log(s-c)=1.07918
________________
3.20951 = log[(s-a)(s-b)(s-c)] (looks about right)
log s = 1.55630
_________________
2)1.65321 >> you subtracted, then divided by 2. Do you have any idea WHY you did these things?
You should be writing:
log[ sqrt((s-a)(s-b)(s-c)/s) = that
___________________
log r=0.82661 << HUH? Where did r come from?
>> Are you simply saying 'call this r = sqrt((s-a)(s-b)(s-c)/s) '
log r=0.82661
log(s-a)=0.9524
________
A
log tan -- = 0.86625-10 << How did you get this number? Say how.
2
Sure you don't mean -1?
A r
tan - = ---
2 s-a
=0.82661
-------
0.95424
=0.86625 minus 1?
...................................
At this point, I think what you mean is:
log[ sqrt((s-a)(s-b)(s-c)/s) = 0.82661
minus log(s-a) = - 0.95424
sqrt[()()()]
log[---------------] = = - 0.13863
s - a
And the rule must be [IT'S ABOUT TIME WE GOT TO THIS.]
sqrt((s-a)(s-b)(s-c)/s
log [-----------------------] = log tan (A/2)
s - a
or, in ordinary mathematics:
sqrt((s-a)(s-b)(s-c)/s)
------------------------ = tan (A/2)
s - a
sqrt((s-a)(s-b)(s-c)/s)
------------------------ = tan (B/2)
s - b
sqrt((s-a)(s-b)(s-c)/s)
------------------------ = tan (C/2)
s - c
Now I think it is time for you to THROW AWAY:
1. Your table of logarithms -- replace it with either a calculator or some skill in using Excel or another spreadsheet.
2. This 'cookbook' you are using -- replace it with a MATH book.
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