Advanced Math/trig

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Question
rationalize the denominator: 2/((the square root of 3)+(the square root of 2))

Answer
Hi Kalie,

The procedure here is the same no matter what the denominator looks like. You want to multiply the top and bottom by the denominator with the middle sign changed.

Here, the bottom is rt(3) + rt(2), so you want to multiply the top and bottom by [rt(3) - rt(2)]:

  2 / [rt(3) + rt(2)] * [rt(3) - rt(2) / rt(3) - rt(2)]

=  [2rt(3) - 2rt(2)] / rt(3)^2 - rt(2)^2

=  [2rt(3) - 2rt(2)] / 1 = 2rt(3) -2rt(2).

This will work because basically you're multiplying on the bottom the from   (A + B)(A - B) = A^2 - B^2, which is what removes the root.

Hope this was clear enough.
Steve

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Steve Holleran

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I can help with all math questions from basic math to Calculus. Whether it`s consumer questions, or questions from high school or college students, I have probably dealt with it at some time in my career.

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33 years teaching experience in NJ public schools

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B.S. Mathematics : Wake Forest University 1972 M.S. Mathematics : Monmouth University 1981

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