Advanced Math/Logarithms

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Question
If log e(x) = -1-log e(y), write down an expression involving x and y which is equal to e^2.

Thank you!

Answer
Hi Selina,

Okay, here's what I see:

      log[e] x = - 1 - log[e] y

      ln x = -1 - ln y       (log[e] = ln)

      ln x + ln y = -1

so     ln (xy) = -1  and that means e^(-1) = xy

      then  e^(-1) = 1/e = xy and then e = 1/(xy)

      so you can write e^2 = 1/(x^2y^2)


Hope this is what you wanted
Steve

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Steve Holleran

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