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QUESTION: 1. 3x + 2y= 6 2. y= 3/2x + 1
ANSWER: Hello Antonia,
This is a good question. Basically, you know that y = 3/2x + 1 always. So you can change the first equation into
3x + 2(3/2x + 1) = 6
3x + 3x + 2 = 6
6x = 4
x = 2/3
Now to find y, you simply substitute the value of x into the second equation.
y = 3/2(2/3) + 1 = 1+1 = 2
so x = 2/3 and y = 2
I hope this helped,
Robi
---------- FOLLOW-UP ----------
QUESTION: I apologize but that was two different problems. So now I'm sure it's a different answer. However thank you for attempt.
Hello again,
Oh, sorry, I misunderstood. Anyways, in this case I'm not sure what you are asking. Do you want me to solve them for y? or x? Or do you want me to graph them and talk about the graph.
Sorry for any misunderstandings.
Robi
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Answers by Expert:
Robi Bhattacharjee
Expertise
I can answer a variety of questions on mathematics. Questions on trigonometry, calculus(preferably single variable), algebra, geometry, and number theory will be answered. I cannot answer questions on abstract branches of mathematics such as group theory. I also cannot answer questions on statistics. In number theory, I can answer questions on congruences, prime numbers, units, functions, and the riemann-zeta function.
Experience
I have studied advanced math my entire life. I started calculus in sixth grade. I have attended numerous math competitions and I am attending math organizations such as the San-Diego math circle. Also, this year I have been invited to the USAMO which is a prestigious math competition (Every year the USAMO invites 500 students from across the USA to participate in this competition. The top 6 go to represent the USA in the International Math Olympiad).
Organizations
I am in the San Diego Math Circle
Education/Credentials
I am entering high school and have received a perfect score and the STAR test 5 times in a row. I also have gotten recognitions in the AMC 10, AIME, Math Counts, and ARML. Additionally, I have won the San Diego Math Olimpiad twice in a row.
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