Expert: Sherman D. - 1/16/2009

Question
QUESTION:
"What is the vertical asymptote(s) of
f(x)= x^2-x-2/x^3-2x^2-5x+6?"

ANSWER: to answer this graphically, all you need to do is graph x^3-2x^2-5x+6

and where ever the graph hits at the x-axis is your vertical asymptotes, because if you have a 0 in the denominator, then your problem would be invalid.

VA = -2, 1, and 3

---------- FOLLOW-UP ----------

QUESTION: Thanks a lot! I was just wondering how you came up with that though...I thought it was unfactorable.

Answer
vertical asymptotes are the easiest to find, because it deals with the denominator. the horizontal asymptotes are the tricky ones.

you can also check out www.quickmath.com, it will factor it for you and solve it for you.

by the way, even if you have

have something in the denominator and numerator that cancel out, the VA will remain the same.