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Question
18xsquared+19=39x
Hi Tim,
For ax² + bx + c = 0
x = [-b ± √(b² - 4ac)] / 2a
So 18x² - 39x + 19 = 0
x = [39 ± √((-39)² - 4.18.19)] / 2(18)
= [39 ± √(1521 - 1368)] / 36
= [39 ± √(153)] / 36
= [39 ± 12.37] / 36
= 1.4269 or 0.7397
Regards
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Answers by Expert:
Ahmed Salami
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I can provide good answers to questions dealing in almost all of mathematics especially from A`Level downwards. I can as well help a good deal in Physics with most emphasis directed towards mechanics.
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An engineering graduate. I have been doing maths and physics all my life.
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