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Question
solve for x. log6(x+2) + log6(x-1)=3 how do you do i solve for x?
Hi Alexandra,
I'm taking the 6 to be the base of logarithm here.
logA + logB = logAB
So,
log6 (x+2) + log6 (x-1) = 3
log6 [(x+2)(x-1)] = 3
Therefore,
(x+2)(x-1) = 6³
x² + x - 2 = 216
x² + x - 218 = 0
You can then solve the quadratic equation to get
x = -15.27 or 14.27
Regards
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Ahmed Salami
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I can provide good answers to questions dealing in almost all of mathematics especially from A`Level downwards. I can as well help a good deal in Physics with most emphasis directed towards mechanics.
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