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Question
Open-top boxes are made by cutting equal squares from the corners of cardboard sheets that measure 32 cm by 28 cm. Determine possible dimensions of the boxes if each has a volume of 1920 cm^3

i have come up with this equation: 1920 = x(32-2x)(28-2x)
what do i do to determine the dimensions?

Answer
Since this is an algebra problem, I would think it would have a simple answer.  Note that 32-x and 28-2x are near 30.  Also note that 30*30 = 900, which is less than half of 1,920.  Since it's less than half, we know that 2 is almost there, but also know that 2 wouldn't work.  Knowing this, let's will try 3.

That would give us 3(32-6)(28-6).
Now 32-6 = 26 and 28-6 = 22.
What we have to do is then determine what the value of 3*26*22 is.
Well, it is clear that 2*25=52, so 22*26 = 572.  Putting this back into the equation gives 3*572 = 1.716.  Nope - that's still to small.

Well, that's to small.  What now?  How about trying 4.
If we put 4 into the equation we get 4(32-8)(28-8).
Now 32-8 is 24 and 28-8 is 20.  Right here it tells me that its promising since 20 ends in a 0 and 1920 ends in 0.  Now if we calculate 4*24*20 we get 4*480.  That looks like 1,600 plus 320, which turns out to be ... 1,920 - bingo!

Isn't that what we were looking for?  

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