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Question
Find the center of a circle with equation x2 - 2x + y2 - 4y - 8 = 0
x^2 - 2x + y^2 - 4y - 8 = 0
x^2 - 2x + y^2 - 4y = 8
(x^2 - 2x + 1 - 1) + (y^2 - 4y + 4 - 4) = 8
(x^2 - 2x + 1) - 1 + (y^2 - 4y + 4) - 4 = 8
add 1 and 4 to both sides.
(x - 1)^2 + (y - 2)^2 = 13
Center : (1,2)
Radius : sqrt(13), just in case you needed to know.
if you use www.quickmath.com to graph it, you will find out that they both are the same equation.
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Sherman D.
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I can answer questions dealing in mathematics of all kinds except for Physics and Calculus, but i can answer questions in Pre-Calculus and Chemistry. I can also answer questions in Recipes of all kinds. I can find games cheats/walkthroughs, but i can`t find a specific game online or offline. I can also do history and recipes for alcoholic beverages.
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Mathematics, Recipes, History, and Games.
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High School graduated. I graduated with honors, and i was in Beta Club for a year and a half.
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Principle's list and A and B honor roll in high school only.
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