Expert: Paul Klarreich - 6/17/2009

Question
Hi Paul,

Could you please ans the following:

Find how many real values of x satisfy the following eqn
log(base x) (2x^2-3x-5)=2

Answer
Questioner:   Avijit Nayek
Country:  United States
Category:  Advanced Math
Private:  No
 
Subject:  Log problem
Question:  Hi Paul,

Could you please ans the following:

Find how many real values of x satisfy the following eqn
log(base x) (2x^2-3x-5)=2
...............................................
Hi, Avijit,

If  log(base x)A = B,  then   x^B = A.

So log(base x) (2x^2-3x-5) = 2  means

x^2 = 2x^2 - 3x - 5,

which is your basic quadratic equation (alas, not factorable).  You can take it from there, I think.