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Question
write each as complex number in standard form, a=bi
1. 13+square root of -16
2.squareof -16 + 4-2i
3.the conjugate of 5-2i
4.(-2+3i) =(9-5i)
5.(5-6i)-(3-4i)
6.(5+2i)4+3i)
7.(-2i)4+3i)
8.(-5i)(6+5i)
9.6+8i)/1-i  

Answer
1.) 13 ± 4i
2.) ±4i + 4 - 2i = 4 - 6i or 4 - 2i
3.) 5 + 2i
4.) -11 + 8i
5.) 2 - 2i
6.) if you mean (5 + 2i)(4 + 3i), then 20 + 15i + 8i + 6i^2 = 20 + 23i - 6 = 14 + 23i
7.) -8i - 6i^2 = 6 - 8i
8.) -30i - 25i^2 = 25 - 30i

9.) Multiply top and bottom by the conjugate of 1 - i
((6 + 8i)(1 + i))/(1 - i^2)
(6 + 6i + 8i + 8i^2)/(1 + 1)
(6 + 14i - 8)/2
(-2 + 14i)/2
-1 + 7i

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