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Question
Hello there,
My question is:
A positive integer n is such that numbers 2n+1 and 3n+1 are perfect squares. Prove that n is divisible by 8.
I would appreciate any help given.
Thankyou.
2n + 1 = x^2
3n + 1 = y^2
2(8) + 1 = 17
2(16) + 1 = 33
2(24) + 1 = 49
2(32) + 1 = 65
2(40) + 1 = 81
3(24) + 1 = 73
3(40) + 1 = 121
using trial and error
n = 40
answers.yahoo.com can probably answer this without needing to use trial and error.
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Sherman D.
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