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How to show dy/dx=((sin2x)/(1-cos2x)) =cotx? Try already using cos2x & sin2x formulae but still can't get it. Please help me. Thanks
Warm~
I think the question is written incorrectly because
((sin2x)/(1-cos2x)) = cotx. You can't 'find' dy/dx unless you know what y is either explicitly or implicitly. We can show ((sin2x)/(1-cos2x)) = cotx are equal like so:
Using sin 2x = 2 sinx cosx and cos 2x = 2cos^2x - 1 we have
2 sinx cosx/(2-2cos^2x) = 2 sinx cosx/2(1-cos^2x) = 2 sinx cosx/2sin^2x
= sinx cosx/sin^2 x = cosx/sinx = cotx. Does this make sense?
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| Comment | Actually the question is not like that. I wrote it that what because i had work through it half way already till there then i can't show it equal to cot x so i ask you. Hehe. Thanks a lot. It does make sense | ||
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Sherry Wallin
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I can answer most questions up through Calculus and some in Number Theory and Abstract Algebra.
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I have had my Bachelor's Degree since 1987 and have been a teacher since 1988. I earned my Masters Degree in Mathematics May 2010. I have been teaching at the same community college since 2002.
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I have taught 12 years at the community college level, medical college, and technical college as well as a high school instructor and alternative education instructor and charter school instructor.
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