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Expert: - 8/22/2009


Question
the third and fourth terms of a sequence are 101 and 83. If the first diffrences are constant, find the first 5 terms of the sequence.

Answer
Questioner: talia
Country: United States
Category: Advanced Math
Private: No
Subject: algebra 1
Question: the third and fourth terms of a sequence are 101 and 83. If the first diffrences are constant, find the first 5 terms of the sequence.
............................................................
It looks as if the common difference is -18. (yes, it can be negative)

So if

a3 = 101
and
a4 = 83 = 101 - 18
then
a5 = 83 - 18
and
a2 = 101 PLUS 18
a1 = 101 PLUS 18 PLUS 18

You can finish up.

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