AllExperts > Advanced Math 
Search      
Advanced Math
Volunteer
Answers to thousands of questions
 Home · More Advanced Math Questions · Answer Library  · Encyclopedia ·
More Advanced Math Answers
Question Library

Ask a question about Advanced Math
Volunteer
Experts of the Month
Expert Login

Awards

About Us
Tell friends
Link to Us
Disclaimer

 
 
 
 
About Paul Klarreich
Expertise
I can answer questions in basic to advanced algebra (theory of equations, complex numbers), precalculus (functions, graphs, exponential, logarithmic, and trigonometric functions and identities), basic probability, and finite mathematics, including mathematical induction. I can also try (but not guarantee) to answer questions on Abstract Algebra -- groups, rings, etc. and Analysis -- sequences, limits, continuity. I won't understand specialized engineering or business jargon.

Experience
I taught at a two-year college for 25 years, including all subjects from algebra to third-semester calculus.

Education/Credentials
-----------

 
   

You are here:  Experts > Science > Mathematics > Advanced Math > Permutations and probabilities

Advanced Math - Permutations and probabilities


Expert: Paul Klarreich - 9/20/2009

Question
I am having trouble figuring out which "formula" to use to get to 3 of my answers. Our professor gave us the answers to the problems, and we are to show the work of how we got to the answer.

1.  Find the number of permutations: P(7, 4).  (The answer he gave us is 840)  (QUESTION: Is it possible I copied the answer down wrong? Because I tried 2 different formulas from my notes, and there is no way I'm coming up with an answer even remotely close to 840)

2.  There are 17 balls: 10 red and 7 blue. What is the probability of getting a red ball?  (answer he gave us is 10/17).

3. Events A and B are independent. Find the probability of A and B if the probability of A is 1/2 (one-half) and the probability of B is 1/3 (one-third).  (the answer he gave us is 1/15)

Thank you so much for your help ...

Answer
Questioner: Lorri
Country: United States
Category: Advanced Math
Private: No
Subject: Need help figuring out which formulas to use
Question: I am having trouble figuring out which "formula" to use to get to 3 of my

answers. Our professor gave us the answers to the problems, and we are to show the

work of how we got to the answer.

1.  Find the number of permutations: P(7, 4).  (The answer he gave us is 840)  

(QUESTION: Is it possible I copied the answer down wrong? Because I tried 2

different formulas from my notes, and there is no way I'm coming up with an answer

even remotely close to 840)

2.  There are 17 balls: 10 red and 7 blue. What is the probability of getting a red

ball?  (answer he gave us is 10/17).

3. Events A and B are independent. Find the probability of A and B if the

probability of A is 1/2 (one-half) and the probability of B is 1/3 (one-third).  

(the answer he gave us is 1/15)

Thank you so much for your help ...
...............................................

1.  Find the number of permutations: P(7, 4).  

This one you could look up, I think:

P(7,4) means permutations of 7 objects, taken 4 at a time.

Isn't that  7!/3!   from   n!/(n-r)!

Or you just analyze:  

7 ways to pick item 1, then
6 ways to pick item 2, then
5 ways to pick item 3, then
4 ways to pick item 4

Then the counting principle gives you  7 6 5 4, which is the same as"
7 6 5 4 3 2 1
-------------
       3 2 1

and that is 840.

.......................................
2.  There are 17 balls: 10 red and 7 blue. What is the probability of getting a red

ball?  (answer he gave us is 10/17).

You are kidding, right?  

p(event K) = (# elements in K)/(# elements in sample space)
...........................................
3. Events A and B are independent. Find the probability of A and B if the

probability of A is 1/2 (one-half) and the probability of B is 1/3 (one-third).  

(the answer he gave us is 1/15)

You reviewed the definition of independent, didn't you?

A, B are independent if  p(A, given B) = p(A), and p(B, given A) = p(B)

And, since  p(A and B) = p(A, given B) * p(B), you can put those together and say:

If A,B are indep, then P(A and B) = p(A) p(B) = 1/2 * 1/3 = 1/6, exactly what the

teacher said.

Hmmmmmm.  Perhaps a misprint somewhere.


Add to this Answer   Ask a Question


 
User Agreement | Privacy Policy | Kids' Privacy Policy | Help
Copyright  © 2008 About, Inc. AllExperts, AllExperts.com, and About.com are registered trademarks of About, Inc. All rights reserved.