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Question
QUESTION: sketch the graph of each function
a) f(x)= absolute value of(x+3) -2
b) g(x)= 1/f(x)

ANSWER: (a) The line would be at a perfect 45 degree angle with an upwards slope in both directions.
|x+3| is 0 when x = -3, so |x+3| - 2 is -2 at x = -3.

This means that it forms a line sloping up from the point (-3,-2)
in both directions at a 45 degree angle.

(b) When f(x) is 1, the functions have the same value.  

When f(x) is 0, g(x) is undefined, so it has an inflection point at these values.

Note that f(x) = 0 is at x+3 = 2 and -x-3 = 2.  That is, x = -1 or x = -5.

Since f(x) is always positive, g(x) is also always positive.

So at the two inflection points, g(x) goes off to +infinity.

As x goes of to +/- infinity, g(x) goes to 0.


---------- FOLLOW-UP ----------

QUESTION: how would i go about graphing (b)?

Answer
Graph
Graph  
a) f(x)= absolute value of(x+3) -2
b) g(x)= 1/f(x)

To graph f(x), note that it is two lines with slope -1 and 1.
They meet at x = -3.  At that point, the function f(x) has a value of -2.
The lines would cross the x axis at -1 and -5.

To graph the function g(x), note that g(x) = 1/f(x).
That means where f(x) is 0, the function is undefined.  That happens where x=-1 and x =-5.
Where f(x) goes off to infinity, g(x) goes to 0.
This happens as x goes off to infinity and minus infinity.



When x>-1 and x<-5, f(x) is positive, which means g(x) is positive.

As the line x=-1 is approached from the left, g(x) goes off to infinity.
As the line x=5 is approached from the right, g(x) goes off to infiniy.

t x = 2 and x = 4, the value of g(x) = 1.

When -5<x<-1, f(x) is negative, so g(x) is negative.
When x=-4 or x=-2, the value of f(x) is -1, so the value of g(x) is -1.
The value of f(-3) is -2, so the value of g(-3) is -1/2.
The function g(x) goes to -infinity as it nears -5 from the right.
The function g(x) goes to -infinity as it nears -1 from the left.

Apply these two the picture sent.  

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