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About Sherry Wallin
Expertise
I can answer most questions up though Calculus and some in Number Theory and Abstract Algebra.

Experience
I have had my Bachelor's Degree since 1987 and have been a teacher since 1988.

Education/Credentials
I have taught 10 years at the community college level, medical college, and technical college as well as a high school instructor and alternative education instructor

 
   

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Advanced Math - math


Expert: Sherry Wallin - 9/26/2009

Question
This is question from absolute value properties
Question
|a|>= and |a|>=-a
Proof: if a>=0  then |a|=a
If a<0 then |a|=-a>a
A belongs to R   then |a|>=a

Please tell me how  it could be  possible that –a>a.i have a doubt in (If a<0 then |a|=-a>a) please explain  

Answer
Hi Pratap~
    First you need to be careful when you type in the problem because this 'a|>= and |a|>=-a' doesn't make sense. To answer your question how can -a > a. What if a = a negative number like -2 then -a = -(-2) = 2 and 2 is certainly greater than -2.

Math Prof

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