Expert: Sherry Wallin - 10/12/2010

Question
QUESTION: (x-6)^2+8
need how to get x-intercepts

ANSWER: Larry~

x-intercepts always occur where y = 0 so set your equation equal to 0 and solve for x.

Math Prof

---------- FOLLOW-UP ----------

QUESTION: whats the answer

Answer
(x-6)^2 = (x-6)(x-6) = x^2-12x+36
now add 8 getting x^2-12x+44 and set it equal to 0:
x^2-12x+44 = 0
Now you have to factor the equation, that is find out what values of x make it true:
This doesn't factor readily so you will need to use the quadratic formula:
x = -(-12)+-sqrt[((-12)^2 -4*1*44)/2(1)]
x = 12+-sqrt[(144-176)/2
you can stop here because this will give imaginary answers and those do not cross the x axis, thus there are no x intercepts.

Math Prof