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Prove: For every x with 1 lessthatn or equal to x less than or equal to 4, x^2-5x+4 is less than or equal to zero
Sarah~
There's not much to prove here since there are only 4 instances to consider so just plug them in and show that they all are less than or equal to 0:
1<=x<=4
1: 1^2-5(1) + 4 = 0
2: 2^2-5(2) + 4 = -2
3: 3^2-5(3) + 4 = -2
4: 4^2-5(4) + 4 = 0
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Sherry Wallin
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I can answer most questions up through Calculus and some in Number Theory and Abstract Algebra.
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I have had my Bachelor's Degree since 1987 and have been a teacher since 1988. I earned my Masters Degree in Mathematics May 2010. I have been teaching at the same community college since 2002.
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I have taught 12 years at the community college level, medical college, and technical college as well as a high school instructor and alternative education instructor and charter school instructor.
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