Advanced Math/Precalculus
Expert: Sherry Wallin - 11/6/2010
QuestionA car's rear windshield wiper rotates 130°. The total length of the wiper mechanism is 25 inches and wipes the windshield over a distance of 14 inches. Find the area covered by the wiper. (Round your answer to one decimal place.)
Also can you please tell me how to do this problem as well?
A wheel of radius 14 in. is rotating at a rate of 2700 rpm. (Enter your answers in terms of π.)
(a) Find the angular speed (in radians per minute).
(b) Find the linear speed of a point on the circumference (in ft/min).
Thanks!
Answer
Kristin~ Here is a revised answer
Here is the answer to your questions with a drawing labeled and attached and below is the written only solutions:
You have an arc with a radius of 11 and an arc with a radius of 25 because you want the 14 sweep so 25 14 = 11. And thus you will want to find the area of the sector covered between the two arcs. You will need the formula for the area of a sector of a circle which is (1/2)r^2*theta. Note you need theta to be in radians so first lets change 130° to radians:
theta = (pi/180)130 = (13/18)pi radians
Now the area of the 130° sector is (1/2)(25^2)(13/18)*pi = 225.69pi and then we will need to subtract off the area of the sector with radius of 11: (1/2)(11^2)(13/18)*pi = 43.69pi =>
and the difference is (225.69 - 43.69)pi = 182pi in^2 which is the area swept out by the 14 inch windshield wiper blade over the 130 deg sweep.
The angular speed omega is defined to be the angle theta measured in radians that is swept out divided by the elapsed time
omega = (2700 rev/min)*(2pi rad/rev)= 5400pi rad/min
Then the linear speed is defined to be v = r*omega so the linear speed is (5400 pi rad/min)(1 ft/12 in)(14 in) = 6300 pi ft/min
Math Prof