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given 3 lines in the plane such that points of intersection form a trianlge with sides 20, 20,20. the number of points equidisitant from all 3 lines is
Sumathi~
There is only one point and it is inside the triangle. Take the triangle and drop a perpendicular from each vertex to the sides opposite and they will cross in exactly one point. This works only because you have an equilateral triangle. Otherwise the three perpendiculars would cross in a single point but they would not be equidistant from all three sides.
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Sherry Wallin
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