Advanced Math/Vector algebra
Expert: Paul Klarreich - 2/6/2010
Question1) A man travelling southward at 15km/h observes that the wind appears to be coming from west. on increasing his speed to 25km/h it appears to be coming from the southwest. find the direction and speed of the wind.
Ans. the wind is coming from a direction 56.18 deg north of west at 18k/hr.
2)A 100kg weight is suspended from the centre of a rope as shown in the adjoining figure. determine the tension in the rope.
Fig.
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|100kg|
Ans. 100kg
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pls help me to find the solution
AnswerQuestioner: renz
Country: Philippines
Category: Advanced Math
Private: No
Subject: VECTOR
Question: 1) A man travelling southward at 15km/h observes that the wind appears to be coming from west. on increasing his speed to 25km/h it appears to be coming from the southwest. find the direction and speed of the wind.
Ans. the wind is coming from a direction 56.18 deg north of west at 18k/hr.
2)A 100kg weight is suspended from the centre of a rope as shown in the adjoining figure. determine the tension in the rope.
Fig.
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\ /
\ /
\120deg/
\ /
\ /
\/
|
|
|
|
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|100kg|
Ans. 100kg
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pls help me to find the solution
1. From the man's point of view, the wind is first:
A vector pointing east at A mph. His southward motion adds an effective 15 mph NORTH to the actual vector of the wind.
so <Wx, Wy> + <15,0> = <0,A>
Then it is:
A vector pointing Northeast at B mph. His southward motion adds an effective 25 mph north to the actual vector of the wind.
so <Wx, Wy> + <25,0> = <B,B>
I think now we have enough info:
Wy = A
Wx + 15 = 0, so Wx = -15, which is 15 mph from the south.
Wx + 25 = B = Wy
-15 + 25 = Wy
Wy = 10, which is 10 mph from the West.
You can do the rest.
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2. If you mean the bottom piece of rope, it is simply the mass it supports, I think.