Advanced Math/Logarithmic equation
Expert: Paul Klarreich - 3/20/2010
QuestionCONSIDER THE FOLLOWING SEQUENCES. WRITE DOWN THE NEXT TWO TERM OF EACH SEQUENCE
log (base 2) 8, log (base 4) 8. log (base 8)8, .....
log (base m) m^k, log (base m^2) m^k....
FIND THE EXPRESSION FOR THE N TERM OF EACH SEQUENCE. WRITE THE EXPRESSION IN THE FORM OF P/q...
2. Log (base 4) 64, log (base 8) 64, log (base 32) 64
Log(base 7)49, Log (base 49)49, log (base 343)49
log (base 1/5) 125, log (base 1/125) 125. log(base1/625)125
describe how to obtain the third answer in each row from the first 2 answer.
AnswerQuestioner: belle
Country: Malaysia
Category: Advanced Math
Private: No
Subject: mATH
Question: CONSIDER THE FOLLOWING SEQUENCES. WRITE DOWN THE NEXT TWO TERM OF
EACH SEQUENCE
log (base 2) 8, log (base 4) 8. log (base 8)8, .....
log (base m) m^k, log (base m^2) m^k....
FIND THE EXPRESSION FOR THE N TERM OF EACH SEQUENCE. WRITE THE EXPRESSION
IN THE FORM OF P/q...
2. Log (base 4) 64, log (base 8) 64, log (base 32) 64
Log(base 7)49, Log (base 49)49, log (base 343)49
log (base 1/5) 125, log (base 1/125) 125. log(base1/625)125
describe how to obtain the third answer in each row from the first 2 answer
...........................................
Logarithm exercises always involve powers. So write:
log (base 2) 8, log (base 4) 8. log (base 8)8, .....
as
log (base 2^1) 2^3, log (base 2^2) 2^3. log (base 2^3)2^3, .....
Do you get the pattern?
....................
And write:
log (base m^1) m^k, log (base m^2) m^k....
likewise, you should get the pattern.
.......................
Now then, for:
Log (base 4) 64, log (base 8) 64, log (base 32) 64
Did you skip a term? Should it be:
Log (base 4) 64, log (base 8) 64, log (base 16) 64,...
which is:
Log (base 2^2) 2^6, log (base 2^3) 2^6, log (base 2^4) 2^6
So your n-th term should be
log (base 2^(n+1)) 2^6
Now what is that? Write:
x = log (base 2^(n+1)) 2^6
and switch to exponential form:
(2^(n+1))^x = 2^6
Now solve:
2^[(n+1)x] = 2^6
(n+1)x = 6
x = 6/(n+1)
See if you can finish up now. Let me know if you run into trouble.