Advanced Math/Series convergence
Expert: Paul Klarreich - 3/7/2010
QuestionFor what values of q>0 is the following series convergent, and find its sum:
1 + q + (q^2)/2 + (q^3)/3 + ... + (q^n)/n
I'm fairly certain that it is convergent for 0 < q < 1, but I don't know how to find the sum and have not been able to find anything helpful online or in my text/lecture notes.
This is for an introductory analysis course, and we are currently studying infinite series and sequences. Thank you, in advance.
AnswerQuestioner: Ray
Country: United States
Category: Advanced Math
Private: No
Subject: series convergence
Question: For what values of q>0 is the following series convergent, and find its sum:
1 + q + (q^2)/2 + (q^3)/3 + ... + (q^n)/n
I'm fairly certain that it is convergent for 0 < q < 1, but I don't know how to find the sum and have not been able to find anything helpful online or in my text/lecture notes.
This is for an introductory analysis course, and we are currently studying infinite series and sequences. Thank you, in advance.
..............................
1 + q + (q^2)/2 + (q^3)/3 + ... + (q^n)/n
You can use the ratio test:
|a[n+1]|
r[n] = ---------
|a[n]|
If lim(n->inf) r[n] < 1, the series converges.
If lim(n->inf) r[n] > 1, the series diverges.
If lim(n->inf) r[n] = 1, we don't know.
In this case:
q^(n+1)/(n+1)
r[n] = --------------
q^n/n
qn
r[n] = -----
n+1
And lim of that = q.
So you need q < 1.
Of course, if q = 1, you have the harmonic series.
I don't know any calculation for the actual sum.