Advanced Math/Modulus
Expert: Sherry Wallin - 4/30/2010
QuestionQUESTION: [x-1] + [2x+3] = 2
find x
[] stands for modulus
ANSWER: What mod are you using? If x = 1 and the mod is 3 then you have [1-1] + [2(1) + 3] = 2 mod 3
Math Prof
---------- FOLLOW-UP ----------
QUESTION: It is not 2 mod 3 ,it is just 2
The mod i am refering is the one in which we take the absolute value of the number
e.g. [-2]=2
AnswerOk, here in America we just use vertical bars to talk about absolute value, so the problem would read like:
| x - 1 | + | 2x + 3 | = 2.
This problem has no solution but I imagine your teacher wants to know how you know this to be true so the following will show your equation has no solution:
Rewrite the equation like so: |x-1| = 2 - |2x+3|
First find where each absolute value is zero: x-1=0 -> x = 1
2x+3 = 0 -> x = -3/2
Take the number line and break it up into intervals with these 'break' points:
intervals (-00,-3/2) (-3/2, 1) (1, 00)
interval numbers #1 #2 #3
In interval #1 both absolute value parts will be negative so remove the vertical bars and take the negative of the expression (or the opposite means the same thing):
-(x-1) = 2 - (2x+3) **it is important and absolutely mandatory to understand this will only give
you results for the specific interval you are in.
-x+1 = 2 - [-(2x -3)]
-x + 1 = 2 + 2x + 3
-x + 1 = 2x + 5
+x +x
1 = 3x + 5
-5 -5
-4 = 3x
/3 /3
-4/3 = x **NOTE -4/3 is NOT in the interval (-00, -3/2) so it can't be a solution
In interval #2 |x-1| will be negative and |2x+3| will be positive so remove the vertical bars and take the opposite of the first -(x-1) and the positive of -(2x+3)
-(x-1) = 2 -(2x+3)
-x + 1 = 2 -2x -3
-x +1 = -1 -2x
+2x +2x
x + 1 = -1
-1 -1
x = -2 **NOTE -2 is not in the interval (-3/2, 1) so it can't be a solution
In interval #3 both absolute value parts will be positive so just remove the vertical bars:
x - 1 = 2 - (2x+3)
x - 1 = 2 - 2x -3
x -1 = -1 -2x
+2x +2x
3x -1 = -1
+1 +1
3x = 0
/3 /3
x = 0 **NOTE 0 is NOT in the interval (1,00) thus there is no solution to the
original absolute value equation. There is no value of x that makes the
statement true.
Math Prof