Advanced Math/Maths-Determinant
Expert: Sherry Wallin - 2/12/2011
QuestionFind the value of
' '
'-1 0 -1 '
' '
' 0 -1 -1 '
' '
'-1 -1 0 '
' '
Answer
Dhananjay~
To find the determinant of a 3x3 matrix you need to choose whether you want to operate on a row or column and then draw a line through the first row and the first column and calculate the determinant of the 2x2 matrix that is left using the element in the first row first column as the multiplier. In your case I chose to use the first column as my operator so that is -1(-1*0--1*-1) = -1(1*-1) = 1
Now go to the 2nd element in column 1 (it will be your next multiplier) and cross out the first column and 2nd row and find the determinant of the remaining 2x2 matrix: 0*(0*0--1*-1) **Note when the multiplier is 0 the whole product will be 0 so it really isn't necessary to do anything but realize you have 0 in your sum that you are acquiring. Now go to the 3rd element in the 1st column and -1 is your multiplier and cross out the first column and 3rd row and find the determinant of the remaining 2x2 matrix as before: -1*(0*-1--1*-1) = -1(0+1*-1) = -1(-1) = 1
So the determinant of this 3x3 matrix is the sum of the three 2x2 matrices determinants that you calculated: 1 + 0 + 1 = 2
One crucial thing you need to note is that the 'sign' on the multiplier may change depending on which element it is. The 'rule' is that you alternate +-+-... in the row or column that you use for your multiplier. In our case the first multiplier is + -1, which is what we used and the 2nd multiplier was 0 so it doesn't matter what sign you use, and the 3rd multiplier will again we + so it is +-1, which is what we used.
I will attached an image of what I am talking about to help you see what I did.
Math Prof