You are here:
- Home
- Science
- Mathematics
- Advanced Math
- Factoring Completely
Advanced Math/Factoring Completely
Advertisement
Question
How do you factor completely 3a^2b+6ab-24b? My math book is of no help. Thank you for your time.
Hi,
3a²b + 6ab - 24b = 3b(a² + 2a - 8)
To factor the term in brackets you need two numbers with a sum of +2 and a product of -8. We have +4 and -2 in this case. So,
a² + 2a - 8 = a² + 4a - 2a - 8
= a(a + 4) - 2(a + 4)
= (a + 4)(a - 2)
Therefore,
3a²b + 6ab - 24b = 3b(a + 4)(a - 2)
Regards
- Add to this Answer
- Ask a Question
Questioner's Rating
| Rating(1-10) | Knowledgeability = 10 | Clarity of Response = 10 | Politeness = 10 |
| Comment | Thank you, that was great. | ||
Related Articles
- mathematics week ten warm ups - questions to begin the school day
- FAQ's About Your Abs - Ab Equipment and Gadgets
- mathematics week nine warm ups - questions to begin the school day
- mathematics week four warm ups - questions to begin the school day
- mathematics week seven warm ups - questions to begin the school day
Advanced Math
Answers by Expert:
Ahmed Salami
Expertise
I can provide good answers to questions dealing in almost all of mathematics especially from A`Level downwards. I can as well help a good deal in Physics with most emphasis directed towards mechanics.
Experience
An engineering graduate. I have been doing maths and physics all my life.
©2012 About.com, a part of The New York Times Company. All rights reserved.