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Input/Output: 1/2, 2/4, 3/8, 4/16, 5/32, 6/64, 7/128

I realize the function continues to double from the one before it, but can't figure out its relation to the input number?

The fractions in this problem were not reduced to make it easy to see the relation.

It can be seen the top is n and the bottom is 2^n.

That is, it is n/2^n.

If n=1, this is 1/2.

If n=2, this is 2/2^2 = 2/4, and that is really 1/2.

If n=3, this is 3/2^3 = 3/(2*2*2) = 3/8.

If n=4, this is 4/2^4 = 4/(2*2*2*2) = 4/16, and that is really 1/4.

If n=5, this is 5/2^5 = 5/(2*2*2*2*2) = 5/32.

If n=6, this is 6/2^6 = 6/(2*2*2*2*2*2) = 6/64, and that is really 3/32.

If n=7, this is 7/2^7 = 7/(2*2*2*2*2*2*2) = 7/128.

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Comment | Thank you! Looks so easy and makes total sense when I see it your way! Thanks much! |

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