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Hi Clyde

I don't really know how to find the derivative of a function like

[f(x)]^2/[g(2x)+2x] and need some help on it.

Thank you for your time,

Sam

To solve problems like this, you apply the usual rules for differentiation:

Quotient rule: (u/v)' = (u'v - uv')/v^2

Here, u=f(x)^2, so u' = 2f(x)f'(x) by the power & chain rules.

Similarly, v=g(2x)+2x, which is 2g'(2x)+2 by the chain rule.

So the answer would be:

[ 2f(x)f'(x)(g(2x)+2x) - f(x)^2 (2g'(2x)+2) ] / [ (2g'(2x)+2)^2 ]

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