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Three consecutive integers have a sum of -414. Determine the three integers. How would you solve this?

Let n be the first integer, then the three consecutive integers are n, (n+1), and (n+2).

"Three consecutive integers have a sum of -414"
n + (n+1) + (n+2) = -414
3n + 3 = -414
3n = -417
n = -139
n+1 = -138
n+2 = -137

The integers are -139, -138, and -137.

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Janet Yang


I can answer questions in Algebra, Basic Math, Calculus, Differential Equations, Geometry, Number Theory, and Word Problems. I would not feel comfortable answering questions in Probability and Statistics or Topology because I have not studied these in depth.


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