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A salesman has a 60% chance of making a sale to any one customer. The behaviour of successive customers is independent. If two customers A and B enter, what is the probability that the salesman will make a sale to A or B.

I find it best to make a diagram.

That would be a box with A and B, only A, only B, and neither.

Note that A and B would be found by multiplying 0.6 * 0.6, and this gives 0.36.

Next, to not have A sell (which is the same chance as not having B sell),

it is 1 - 0.6 = 0.4. This makes the chance of neither be 0.4 * 0.4 = 0.16.

The chance of only A is then 0.6 * 0.4 = 0.24.

This is the same as only B.

What we would be looking for would be A and B + only A + only B = 0.36 + 0.24 + 0.24 = 0.84.

Another way to do it is to note that what we are looking for is the same as one minus the chance of neither, and that is 1 - 0.16 = 0.84.

Both give the same answer.

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I can answer any question in general math, arithetic, discret math, algebra, box problems, geometry, filling a tank with water, trigonometry, pre-calculus, linear algebra, complex mathematics, probability, statistics, and most of anything else that relates to math. I can also say that I broke 5 minutes for a mile, which is over 12 mph, but is that relevant?

Experience in the area; I have tutored people in the above areas of mathematics for over two years in AllExperts.com. I have tutored people here and there in mathematics since before I received a BS degree back in 1984. In just two more years, I received an MS degree as well, but more on that later.
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I worked at The Boeing Company for over 5 years.
I received an MS degreee in Mathematics from Oregon State Univeristy.
The classes I took were over 100 hours of upper division credits in mathematical courses such as
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I graduated with honors in both my BS and MS degrees.
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**Education/Credentials**

Master of Science at OSU with high honors in mathematics.
Bachelor of Science at OSU with high honors in mathematical sciences.
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