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Dear Prof Randy

http://en.wikipedia.org/wiki/Shakuntala_Devi

I was trying to trace the algorithm/logic/method for Calculating 23rd Root of a 201 Digit Whole Number.

1. Number 9 is a single digit number, Number 99 is a two digit number, Number 999 is a three digit number and so on ....

2. First find the square root, cube root, 4th root, 5th root, till 23rd root of 9 with help of scientific calculator / computer

3. Similarly find the square root, cube root, 4th root, 5th root, till 23rd root of 99, 999, 9999, 99999, 999999, 9999999 till the number 9 suffix with number 9 - 201 times with help of scientific calculator / computer.

4. This will give us 23root of a 201 digit number 9 suffix with number 9 - 201 times.

But to calculate a 23rd root of any random number will be some other method ?

Will the above method/logic help to some extend ?.

Awaiting your reply,

Thanks & Regards,

Prashant S Akerkar

I'm afraid I don't understand your algorithm with the numbers made up of multiple 9s. If I was to find the 23rd root of a huge number N I would first calculate y = log(N^1/23) = (1/23)log(N) and then get 10^y = N^(1/23). I also note that log10(201) = 2.3, so maybe you are thinking of your number 23 = A^2 as an intensity (A = amplitude) and finding the dB = 20log10(A). Why you would do this I have no idea!

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Comment | Dear Prof Randy Thank you. Thanks & Regards, Prashant S Akerkar |

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