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I am not clear on this part of your solution:

dimensions of picture: (L-4) inches by (W-4) inches

area of picture = (L-4)(W-4) = LW - 4W - 4L + 16 inē

LW - (LW - 4W - 4L + 16) = 152

4W + 4L = 168

W + L = 42"

Thanks again.

L and W are the dimensions of the whole thing, i.e., picture surrounded by frame.

The horizontal width of the picture is W - left frame - right frame = W - 2 - 2 = W - 4 inches:

https://www.flickr.com/photos/dwread/14139979715/

Similarly, the vertical length of the picture is L - frame above - frame below = L - 2 - 2 = L - 4 inches.

Therefore, the area of the picture is (L-4)(W-4) inē.

area of frame = combined area of picture and frame - area of picture

152 inē = LW - (L-4)(W-4)

This reduces to

W + L = 42 in

Since the length is twice the width,

W = 14 in

L = 28 in

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