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Dear Janet. I write mystery novels.

I'm working on a project involving a safe, with a combination lock - 4 numbers, from0 to 99.

a character has the first number. How many possible combnations would there be to get the next 3.

I know this would not be possible, but I want to explain to the reader just how difficult it would be.

Thank you,

Jerry Kennealy

There are 1000 possibilities for the last three digits. There happens to be a very good explanation of this very problem at http://www.mathsisfun.com/combinatorics/combinations-permutations.html, section 1.

Revision:

One THOUSAND, not one hundred!

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