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Question
Question 2.4
Question 2.4  
Kindly help me with this question..This isn't homework, i am just trying to work through problems as i am helping my son with his maths as he is disadvantage.

I have done most of the questions but i am stuck with question 2.4. So the assistance would really be appreciated...

I have attached a picture regarding the question as the link doesn't work.

Answer
You know from solving question 2.1 that the vertex of the parabola is D(-1, 4).

Find the distance d between A(-3, 0) and D(-1, 4):
rise = 4 - 0 = 4
run = -1 - (-3) = 2

By the Pythagorean Theorem,
d = rise + run = 4 + 2 = 20
d = √20 = 2√5
:::::
Equation for circle of radius r, centered at (h, k):
 (x-h) + (y-k) = r

So the equation for the circle of radius 2√5, centered at A(-3, 0) is:
 (x+3) + y = 20
https://www.flickr.com/photos/dwread/14593721683/
:::::
Question 2.6
You already know from solving questions 2.1 and 2.2 that
 f(x) = -x - 2x + 3
 g(x) = 2x + 6

Let u(x) = f(x) - g(x) = -x - 4x - 3.
When u(x) is a maximum, u'(x) = 0
u'(x) = -2x - 4 = 0
x = -2
u(-2) = -(-2) - 4(-2) - 3 = 1
The maximum vertical distance between f and g is 1.

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Janet Yang

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I can answer questions in Algebra, Basic Math, Calculus, Differential Equations, Geometry, Number Theory, and Word Problems. I would not feel comfortable answering questions in Probability and Statistics or Topology because I have not studied these in depth.

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I tutor students (fifth through twelfth grades) and am a Top Contributor on Yahoo!Answers with over 24,000 math solutions.

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