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The capacity of a tank is to be doubled by increasing each dimension by the same amount.  Determine new dimensions.

Old dimensions: 3 x 4 x 5 feet.

Note: Solve algebraically.

Volume of tank = 3򉕙 = 60 ft

Increase length, width, and height by n ft each, then the volume becomes (n+3)(n+4)(n+5) ft.
(n+3)(n+4)(n+5) = 120
n + 12n + 47n + 60 = 120
n + 12n + 47n - 60 = 0
n = 1

New dimensions: 4 ft by 5 ft by 6 ft

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Janet Yang


I can answer questions in Algebra, Basic Math, Calculus, Differential Equations, Geometry, Number Theory, and Word Problems. I would not feel comfortable answering questions in Probability and Statistics or Topology because I have not studied these in depth.


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