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The capacity of a tank is to be doubled by increasing each dimension by the same amount. Determine new dimensions.

Old dimensions: 3 x 4 x 5 feet.

Note: Solve algebraically.

Volume of tank = 3·4·5 = 60 ft³

Increase length, width, and height by n ft each, then the volume becomes (n+3)(n+4)(n+5) ft³.

(n+3)(n+4)(n+5) = 120

n³ + 12n² + 47n + 60 = 120

n³ + 12n² + 47n - 60 = 0

n = 1

New dimensions: 4 ft by 5 ft by 6 ft

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