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Question: Show that log of base 2 (72) = m + 2log of base 2 (3).

Hi Jordan,

We know that log(2) A + log(2) B = log(2) [AB]

and log(2) [A^n] = n log(2) A

So,

log(2) 72 = log(2) [8 x 9]

= log(2) [2³ x 3²]

= log(2) 2³ + log(2) 3²

= 3 log(2) 2 + 2 log(2) 3

= 3 + 2 log(2) 3 (since log(2) 2 = 1)

Hope it was easy to follow.

Regards

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