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QUESTION: Is it possible to calculate the amount of water in a cylinder based off of the information that I have.

I have the exit pipe diameter

I have the rate of flow coming out of said pipe

I have the circumference and can get the height of said cylinder

I was able to calculate velocity based on pipe diameter and flow rate.

I need to be able to calculate the total amount of water "or rough percentage" based on what i have, or other information i may be able to gather. Is this possible?

ANSWER: According to http://www.slideshare.net/NonnieZ/pressure-vs-rate-of-flow

the equation for the pressure of water flow is

P = pgh {where the p is really a greek rho}.

Now p is the pressure of the water at that point,

g is the gravitational constant, and

h is the height of the water.

You can calculate the liters exiting per minute based on finding the area of the circle (calculated from the raidus r as πr²) and how fast the water is coming out.

Since you have said the P and p are known, and g is known as well, this means that h can be calculated. The equation of this is h = P/(pg).

---------- FOLLOW-UP ----------

QUESTION: I'm not sure I understand how to calculate P.

p and g i understand "i believe" 9.81 and 1,000.

But I don't understand what P represents and how to get it.

We have P = pgh { where is p is used for rho }. In this equation, P is pressure in Pa,

p is the density in kg/m^3, g is gravity (9.81m/s²), and h is the depth of the liquid.

Now Pa in this equation is the pressure in terms of N/m² where N is Newtons and m is for meters.

A Newton in this equation is in the form of kg/s².

I believe p and g are given in reverse, for I know gravity is 9.81m/s².

Form this, it looks like p is 1,000kg/m³.

To get P, it looks like we need to integrate pgh for p = 0 (at the surface) to p = B

(B is the distance in meters to the bottom of the tank in terms of h.

That means there is a dh at the end of the integral.

When this is integrated, the answer is pgB²/2.

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