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Hello, i have a question i missed class due to a flue and im not sure how to solve this quesstion
Find a simplified formula for the function

m(x)= 3x^2, n(x)=2x, o(x)= Sqroot of x+2

m(o(x))n(x)

my answer is 2x(3x+6-sqroot of x+2)  

Answer
m(o(x)) = m(sqrt(x + 2))
m(sqrt(x + 2)) = 3(sqrt(x + 2))^2 = 3(x + 2) = 3x + 6

m(o(x)) = 3x + 6
m(o(x)) * n(x) = (3x + 6)(sqrt(x + 2))

m(o(x)) * n(x)) = (3x + 6)sqrt(x + 2) or 3xsqrt(x + 2) + 6sqrt(x + 2)

This is assuming you meant m(o(x)) * n(x) and not m(o(n(x))) or m(o(x) * n(x)) or anything differently than what am assuming.

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If your problem had been

(n(x))*(m(o(x)) - o(x))

Keep in mind, this doesn't mean

(n(x))*(o(x))(m - 1)

just treat m(o(x)) as m(a) where "a" = sqrt(x + 2)

If you have anymore, just let me know.

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