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Expert: Sherman D. - 7/7/2005


Question
List all the possible rational zeros of p(x)=2x^3-3x^2+4x-6.

Answer
p(x) = 2x^3 - 3x^2 + 4x - 6

2x^3 - 3x^2 + 4x - 6 = (2x^3 + 3x^2) + (4x - 6)

(2x^3 - 3x^2) + (4x - 6) = x^2(2x - 3) + 2(2x - 3)

since both x^2 and 2 have (2x - 3) as a factor, you can combine them to get

(x^2 + 2)(2x - 3)

x = -isqrt(2), isqrt(2), (3/2)

however since you wanted rational zeros only,

x = (3/2)

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Sherman D.

Expertise

I can answer questions dealing in mathematics of all kinds except for Physics and Calculus, but i can answer questions in Pre-Calculus and Chemistry. I can also answer questions in Recipes of all kinds. I can find games cheats/walkthroughs, but i can`t find a specific game online or offline. I can also do history and recipes for alcoholic beverages.

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Mathematics, Recipes, History, and Games.

Education/Credentials
High School graduated. I graduated with honors, and i was in Beta Club for a year and a half.

Awards and Honors
Principle's list and A and B honor roll in high school only.

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