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Expert: Sherman D. - 7/24/2007


Question
QUESTION: Can you please help and explain how to calculate teh value of the discriminant of x^2+4x+4=0

ANSWER: ax^2 + bx + c = 0
d = b^2 - 4ac

1x^2 + 4x + 4 = 0

d = 4^2 - 4(1)(4)
d = 16 - 16
d = 0

This means that the graph hits at the x-axis only once.

---------- FOLLOW-UP ----------

QUESTION: May I ask why it hits only once?

Answer
lets do it this way

(ax + c)(bx + d) means that you have 2 connections
(ax + c)^2 means you have 1 connection
(ax + ci)(bx + di) means you have no connection

x^2 + 4x + 4 = (x + 2)^2, so you only have one connection since the only possible x value that will get you a 0 answer is -2.

(-2)^2 + 4(-2) + 4
4 - 8 + 4
-4 + 4
0

so you only have one x-intercept value.

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Sherman D.

Expertise

I can answer questions dealing in mathematics of all kinds except for Physics and Calculus, but i can answer questions in Pre-Calculus and Chemistry. I can also answer questions in Recipes of all kinds. I can find games cheats/walkthroughs, but i can`t find a specific game online or offline. I can also do history and recipes for alcoholic beverages.

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Mathematics, Recipes, History, and Games.

Education/Credentials
High School graduated. I graduated with honors, and i was in Beta Club for a year and a half.

Awards and Honors
Principle's list and A and B honor roll in high school only.

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