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Question
How many liters of a 35% aciid solution should be mixed with a 14% acid solution to oobtain 70 liters of a 20% acid solution?
.35x + .14y = 70(.2)
.35x + .14y = 1.4
35x + 14y = 140
5x + 2y = 20
x + y = 70
5x + 2y = 20
Multiply top by -2
-2x - 2y = -140
5x + 2y = 20
3x = -120
x = -40
x + y = 70
-40 + y = 20
y = 110
So you have to subtract 40 liters of the 35% solution and add 110 liters of the 14% solution to get a 20% solution out of 70 liters.
info found at http://mathforum.org/library/drmath/view/52858.html
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Sherman D.
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I can answer questions dealing in mathematics of all kinds except for Physics and Calculus, but i can answer questions in Pre-Calculus and Chemistry. I can also answer questions in Recipes of all kinds. I can find games cheats/walkthroughs, but i can`t find a specific game online or offline. I can also do history and recipes for alcoholic beverages.
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