Expert: Sherman D. - 5/5/2006

Question
Give Max number of zeros the poly function may have use Descarte's Rule of Signs
f(x)=-9x^7+x^3-x^2+4


Vertical Asymptotes  f(x)=x-7/x^2-25

List potentianl rational zero of poly:  f(x)=5x^3-x^2+2

Find Rational Zeros of polynomial: f(x)=x^3+3x^2-4x-12

Answer
Give Max number of zeros the poly function may have use Descarte's Rule of Signs
f(x)=-9x^7+x^3-x^2+4

The signs change 3 times, so there are a 3 possible zeros.

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Vertical Asymptotes
f(x) = (x - 7)/(x^2 - 25)
f(x) = (x - 7)/((x - 5)(x + 5))

VA : x = 5 and -5

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List potentianl rational zero of poly: f(x)=5x^3-x^2+2

Using quickmath.com, x = -.67581

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Find Rational Zeros of polynomial: f(x)=x^3+3x^2-4x-12  

f(x) = x^3 + 3x^2 - 4x - 12
f(x) = (x^3 + 3x^2) + (-4x - 12)
f(x) = x^2(x + 3) - 4(x + 3)
f(x) = (x^2 - 4)(x + 3)
f(x) = (x - 2)(x + 2)(x + 3)

x = 2, -2, or -3

Sorry i couldn't do better on 5x^3 - x^2 + 2. Maybe answers.yahoo.com can help you.